Ответ:
x1=1/5, x2=125
Объяснение:
log(5,x) = t
t^2-2t-3=0
t1=-1 t2 =3
log(5,x)=-1
x>0
x = 5^(-1)=0.2
log(5,x)=3
x =5^3 = 125
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Ответ:
x1=1/5, x2=125
Объяснение:
log(5,x) = t
t^2-2t-3=0
t1=-1 t2 =3
log(5,x)=-1
x>0
x = 5^(-1)=0.2
log(5,x)=3
x =5^3 = 125