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vladmakarchuk80
@vladmakarchuk80
July 2022
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Решите 2,3,4пожалуйста. Заранее СПАСИБО!!!)
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sedinalana
Решение смотри на фотографии
0 votes
Thanks 1
manyny06
Verified answer
2
a)1,5m²n-7,5m³=1,5m²(n-5n)
6(k+3)+n(k+3)=(k+3)(6+n)
b)4k²-16=4(k²-4)=4(k-2)9k+2)
7ab+b+7ac+c=b(7a+1)+c(7a+1)=(7a+1)(b+c)
3
a)(62²-22²)/(25²-15²)=(62-22)(62+22)/[(25-15)(25+15)]=(40*88)/(10*40)=8,8
b)ab-ac-3b+3c-7kb+7kc=a(b-c)-3(b-c)-7k(b-c)=(b-c)(a-3-7k)
4
a)1/5*x³-3,4x²=0
x³-17x²=0
x²(x-17)=0
x=0
x-17=0⇒x=17
b)2/9*x(4-x)-6(x-4)=0
2/9*x(4-x)+6(4-x)=0
(4-x)*(2/9*x+6)=0
4-x=0⇒x=4
2/9*x+6=0⇒2/9*x=-6⇒x=-6:2/9=-6*9/2=-27
1 votes
Thanks 1
vladmakarchuk80
а где второе фото?
manyny06
есть?
vladmakarchuk80
где?
vladmakarchuk80
смотреть?
vladmakarchuk80
manyny06
vladmakarchuk80
ау
vladmakarchuk80
скинь фото ещё
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Answers & Comments
Verified answer
2a)1,5m²n-7,5m³=1,5m²(n-5n)
6(k+3)+n(k+3)=(k+3)(6+n)
b)4k²-16=4(k²-4)=4(k-2)9k+2)
7ab+b+7ac+c=b(7a+1)+c(7a+1)=(7a+1)(b+c)
3
a)(62²-22²)/(25²-15²)=(62-22)(62+22)/[(25-15)(25+15)]=(40*88)/(10*40)=8,8
b)ab-ac-3b+3c-7kb+7kc=a(b-c)-3(b-c)-7k(b-c)=(b-c)(a-3-7k)
4
a)1/5*x³-3,4x²=0
x³-17x²=0
x²(x-17)=0
x=0
x-17=0⇒x=17
b)2/9*x(4-x)-6(x-4)=0
2/9*x(4-x)+6(4-x)=0
(4-x)*(2/9*x+6)=0
4-x=0⇒x=4
2/9*x+6=0⇒2/9*x=-6⇒x=-6:2/9=-6*9/2=-27