решите биквадратное уравнение:
х^4-29x^2+100=0
x²=n
n²-29n+100=0
Δ=841-400=441
√Δ=21
n₁=(29-21)/2=25
n₂=4
x²=25 v x²=4
x₁=-5 v x₂=5 v x₃=-2 v x₄=2
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Verified answer
х^4-29x^2+100=0
x²=n
n²-29n+100=0
Δ=841-400=441
√Δ=21
n₁=(29-21)/2=25
n₂=4
x²=25 v x²=4
x₁=-5 v x₂=5 v x₃=-2 v x₄=2