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MissWei
@MissWei
July 2022
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Dимасuk
Verified answer
√(1 + cos2x) = 3/2 - sin²x
Разложим cos2x по формуле косинуса удвоенного аргумента:
cos2x = 2cos²x - 1
√(1 + 2cos²x - 1) = 3/2 - sin²x
√2·cosx = 3/2 - sin²x= 0
Воспользуемся основным тригонометрическим тождеством:
sin²x + cos²x = 1 ⇔ sin²x = 1 - cos²x.
√2·cosx = 3/2 - (1 - cos²x)
√2·cosx = 1/2 + cos²x
cos²x - √2·cosx + 1/2 = 0
(cosx - √2/2)² = 0
cosx - √2/2 = 0
cosx = √2/2
x =
±
π/4 + 2πn, n ∈ Z
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Answers & Comments
Verified answer
√(1 + cos2x) = 3/2 - sin²xРазложим cos2x по формуле косинуса удвоенного аргумента:
cos2x = 2cos²x - 1
√(1 + 2cos²x - 1) = 3/2 - sin²x
√2·cosx = 3/2 - sin²x= 0
Воспользуемся основным тригонометрическим тождеством:
sin²x + cos²x = 1 ⇔ sin²x = 1 - cos²x.
√2·cosx = 3/2 - (1 - cos²x)
√2·cosx = 1/2 + cos²x
cos²x - √2·cosx + 1/2 = 0
(cosx - √2/2)² = 0
cosx - √2/2 = 0
cosx = √2/2
x = ±π/4 + 2πn, n ∈ Z