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@Надюлик
June 2022
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решите неравенство
4^(x)+2^(x+2)>5
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sharadi
Verified answer
2²ˣ + 2ˣ⁺² - 5 > 0
2ˣ = t
t² +4t -5 > 0 Корни -5 и 1
-∞ -5 1 +∞
+ - + это знаки t² +4t -5
IIIIIIIIIIIIIIIIII IIIIIIIIIIIIIIIIIII
a) t > -5 б) t < 1
2ˣ > -5 2ˣ < 1
x - любое x < 0
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Answers & Comments
Verified answer
2²ˣ + 2ˣ⁺² - 5 > 02ˣ = t
t² +4t -5 > 0 Корни -5 и 1
-∞ -5 1 +∞
+ - + это знаки t² +4t -5
IIIIIIIIIIIIIIIIII IIIIIIIIIIIIIIIIIII
a) t > -5 б) t < 1
2ˣ > -5 2ˣ < 1
x - любое x < 0