Решите неравенство log5(x+2)+log5(1-x)<=log5((1-x)(x^2-8x-8))
log5 (x+2)*(1-x) <=log5 ((1-x)(x^2-8x-8))
(x+2)(1-x)<=(1-x)(x^2-8x -8)
x+2<=x^2-8x-8
x^2-9X-10>=0
D= 81+40=121; sqrt (D)= 11
x1=(9-11)/2=-1
x2=(9+11)/2= 2
(x+1)*(x-2)>=0
x Є (-∞ ; -1] U [2; + ∞)
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log5 (x+2)*(1-x) <=log5 ((1-x)(x^2-8x-8))
(x+2)(1-x)<=(1-x)(x^2-8x -8)
x+2<=x^2-8x-8
x^2-9X-10>=0
D= 81+40=121; sqrt (D)= 11
x1=(9-11)/2=-1
x2=(9+11)/2= 2
(x+1)*(x-2)>=0
x Є (-∞ ; -1] U [2; + ∞)