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Yana11991199
@Yana11991199
July 2022
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решите неравенство под номером 10, пожалуйста!!!!!!!!!!!!!!
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sangers1959
Verified answer
2sin²x+sinx-1<0
sinx=t
2t²+t-1=0 D=9
t₁=-1 t₂=1/2
(t+1)(t-1/2)<0
-∞_____+_______-1______-______1/2_____________+∞
-1<t<1/2
-1<sinx<1/2
-π/2+2πn<x<π/6+2πn.
1 votes
Thanks 1
Yana11991199
спасибо!!!!!!!!!!!!
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Answers & Comments
Verified answer
2sin²x+sinx-1<0sinx=t
2t²+t-1=0 D=9
t₁=-1 t₂=1/2
(t+1)(t-1/2)<0
-∞_____+_______-1______-______1/2_____________+∞
-1<t<1/2
-1<sinx<1/2
-π/2+2πn<x<π/6+2πn.