Home
О нас
Products
Services
Регистрация
Войти
Поиск
Yana11991199
@Yana11991199
March 2022
1
21
Report
в скобках 2 и 4............
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sedinalana
Verified answer
1
(2x-1)(2x+1)/(x+3)<0
x=1/2 x=-1/2 x=-3
_ + _ +
-------------------(-3)------------(-1/2)---------(1/2)--------------------
x∈(-∞;-3) U (-1/2;1/2)
2
(4-2^(3-x))/(x-1)(x+1)≥0
4-2^(3-x)=0⇒2^(3-x)=4⇒3-x=2⇒x=1
x-1=0⇒x=1
x+1=0⇒x=-1
_ _ +
------------(-1)-----------------(1)-----------------------
+ _ +
x∈(1;1) U (1;∞)
0 votes
Thanks 0
More Questions From This User
See All
Yana11991199
August 2022 | 0 Ответы
22x 1 najdite proizvodnuyu
Answer
Yana11991199
July 2022 | 0 Ответы
reshite neravenstvo pod nomerom 10 pozhalujsta
Answer
Yana11991199
March 2022 | 0 Ответы
kak iz etena poluchit 12 dihloretan kak iz 12 dihloretana poluchit etin kak iz
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "в скобках 2 и 4..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
1(2x-1)(2x+1)/(x+3)<0
x=1/2 x=-1/2 x=-3
_ + _ +
-------------------(-3)------------(-1/2)---------(1/2)--------------------
x∈(-∞;-3) U (-1/2;1/2)
2
(4-2^(3-x))/(x-1)(x+1)≥0
4-2^(3-x)=0⇒2^(3-x)=4⇒3-x=2⇒x=1
x-1=0⇒x=1
x+1=0⇒x=-1
_ _ +
------------(-1)-----------------(1)-----------------------
+ _ +
x∈(1;1) U (1;∞)