ОДЗ x>0
log(2)x=t
t^2+5t+6>0
D=25-24=1
t1=(-5+1)/2=-2 log(2)x=-2; x=1/4
t2=(-5-1)/2=-3; x=1/8
(0)++++(1/8)-----(1/4)++++
Ответ x=(0;1/8)U(1/4;+∞)
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ОДЗ x>0
log(2)x=t
t^2+5t+6>0
D=25-24=1
t1=(-5+1)/2=-2 log(2)x=-2; x=1/4
t2=(-5-1)/2=-3; x=1/8
(0)++++(1/8)-----(1/4)++++
Ответ x=(0;1/8)U(1/4;+∞)