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zvarichr
@zvarichr
July 2022
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Решите первое. пожалуйстааа
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Удачник66
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1) а) √3*sin 60 + cos 60*sin 30 - tg 45*ctg 135 + ctg 90 =
= √3*√3/2 + 1/2*1/2 - 1*(-1) + 0 = 3/2 + 1/4 + 1 = 7/4 + 1 = 2 3/4 = 11/4
б) cos (pi/6) - √2*sin (pi/4) + √3*tg (pi/3) = √3/2 - √2*1/√2 + √3*√3 =
= √3/2 - 1 + 3 = 2 + √3/2
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amin07am
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Answers & Comments
Verified answer
1) а) √3*sin 60 + cos 60*sin 30 - tg 45*ctg 135 + ctg 90 == √3*√3/2 + 1/2*1/2 - 1*(-1) + 0 = 3/2 + 1/4 + 1 = 7/4 + 1 = 2 3/4 = 11/4
б) cos (pi/6) - √2*sin (pi/4) + √3*tg (pi/3) = √3/2 - √2*1/√2 + √3*√3 =
= √3/2 - 1 + 3 = 2 + √3/2
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