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acar
@acar
August 2022
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Решите пожалуйста 10 пример
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sedinalana
Verified answer
1)1/(x+2)+5/[(x+2)(x-3)]+2x/(x-3)=(x-3+5+2x²+4x)/[(x+2)(x-3)]=
=(2x²+5x+2)/[(x+2)(x-3)]=(2x+1)(x+2)/[(x+2)(x-3)=(2x=1)/(x-3)
x²-x-6=(x-3)(x+2)
x1=x2=1 U x1*x2=-6⇒x1=-2 U x2=3
2x²+5x+2=2(x+1/2)(x+2)=(2x+1)(x+2)
D=25-16=9
x1=(-5+3)/4=-1/2 U x2=(-5-3)/4=-2
2)(2x+1)/(x-3)*x/(2x+1)=x/9x-3)
3)x/(x-3)+(x-9)/[2(x-3)]=(2x+x-9)/[29x-3)]=(3x-9)/[2(x-3)]=
=3(x-3)/[2(x-3)]=3/2=1,5
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Answers & Comments
Verified answer
1)1/(x+2)+5/[(x+2)(x-3)]+2x/(x-3)=(x-3+5+2x²+4x)/[(x+2)(x-3)]==(2x²+5x+2)/[(x+2)(x-3)]=(2x+1)(x+2)/[(x+2)(x-3)=(2x=1)/(x-3)
x²-x-6=(x-3)(x+2)
x1=x2=1 U x1*x2=-6⇒x1=-2 U x2=3
2x²+5x+2=2(x+1/2)(x+2)=(2x+1)(x+2)
D=25-16=9
x1=(-5+3)/4=-1/2 U x2=(-5-3)/4=-2
2)(2x+1)/(x-3)*x/(2x+1)=x/9x-3)
3)x/(x-3)+(x-9)/[2(x-3)]=(2x+x-9)/[29x-3)]=(3x-9)/[2(x-3)]=
=3(x-3)/[2(x-3)]=3/2=1,5