|x - 2| + |x + 2| = |3 - x|
1) x < - 2
- (x - 2) - (x + 2) = 3 - x
- x + 2 - x - 2 = 3 - x
- 2x + x = 3
- x = 3
x = - 3
2) - 2 ≤ x < 2
- (x - 2) + (x + 2) = 3 - x
- x + 2 + x + 2 = 3 - x
x = - 1
3) 2 ≤ x < 3
(x - 2) + (x + 2) = 3 - x
x - 2 + x + 2 = 3 - x
2x = 3 - x
3x = 3
x = 1 - неуд , так как 1 ∉ [2 , 3)
4) x ≥ 3
(x - 2) + (x + 2) = - (3 - x)
x - 2 + x + 2 = - 3 + x
2x = x - 3
x = - 3 - неуд, так как - 3 ∉ [3 ; + ∞)
Ответ : - 3 - 1 = - 4
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|x - 2| + |x + 2| = |3 - x|
1) x < - 2
- (x - 2) - (x + 2) = 3 - x
- x + 2 - x - 2 = 3 - x
- 2x + x = 3
- x = 3
x = - 3
2) - 2 ≤ x < 2
- (x - 2) + (x + 2) = 3 - x
- x + 2 + x + 2 = 3 - x
x = - 1
3) 2 ≤ x < 3
(x - 2) + (x + 2) = 3 - x
x - 2 + x + 2 = 3 - x
2x = 3 - x
3x = 3
x = 1 - неуд , так как 1 ∉ [2 , 3)
4) x ≥ 3
(x - 2) + (x + 2) = - (3 - x)
x - 2 + x + 2 = - 3 + x
2x = x - 3
x = - 3 - неуд, так как - 3 ∉ [3 ; + ∞)
Ответ : - 3 - 1 = - 4