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lermolen
@lermolen
June 2022
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Решите пожалуйста, (a+1)^2+3(a-2)^2-5(a-1)(a+1) ответ 9 - 4a - a^2
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Sadikta
(a+1)^2+3(a-2)^2-5(a-1)(a+1)(а+1)² + 3(а-2)² - 5(а-1)(а+1) = а²+2а+1+ 3(а²-4а+4) -5(а²-1)= а²+2а+1+ 3а² -12а+12- 5а² +5= -а² -10а+18
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Thanks 1
Sadikta
)(а+1)² + 3(а-2)² - 5(а-1)(а+1) = а²+2а+1+ 3(а²-4а+4) -5(а²-1)= а²+2а+1+ 3а² -12а+12- 5а² +5= -а² -10а+18
lermolen
спасибо, конечно, но ответ не сошёлся!
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