Решите пожалуйста, без дробей. Created by korneliikarp2006. algebra-ru

подставляем a=90, b=48:ОТВЕТ: 15

Решите пожалуйста, без дробей...

sunnatxoja77

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$2b+\frac{8a-2b^2}{b}=\frac{2b^2+8a-2b^2}{b}=\frac{8a}{b}$

подставляем a=90, b=48:

$\frac{8*90}{48}=15$

ОТВЕТ: 15

1 votes Thanks 2

Universalka

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$2b+\frac{8a-2b^{2}}{b}=\frac{2b^{2}+8a-2b^{2}}{b}=\frac{8a}{b}\\\\a=90;b=48\Rightarrow \frac{8a}{b}=\frac{8*90}{48}=\frac{8*6*15}{8*6}=15\\\\Otvet:\boxed{15}$

2 votes Thanks 1

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