sinA = 21/29
По формуле sin²A + cos²A = 1 выражаем cos²A:
cos²A = 1 - sin²A = 1 - (21/29)² = 1 - 441/841 = (841 - 441)/841 = 400/841
Тогда cosA = 20/29
По формуле ctgA = cosA/sinA считаем ctgA:
ctgA = (20/29)/(21/29) = 20/21
Ответ: ctgA = 20/21.
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
sinA = 21/29
По формуле sin²A + cos²A = 1 выражаем cos²A:
cos²A = 1 - sin²A = 1 - (21/29)² = 1 - 441/841 = (841 - 441)/841 = 400/841
Тогда cosA = 20/29
По формуле ctgA = cosA/sinA считаем ctgA:
ctgA = (20/29)/(21/29) = 20/21
Ответ: ctgA = 20/21.