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lavgustin
@lavgustin
August 2022
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Решите пожалуйста. (х-3)(х-4)(х-5)=(х-2)(х-4)(х-5)
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Ртуть3
Verified answer
(х-3)(х-4)(х-5)=(х-2)(х-4)(х-5)
(х-3)(х-4)(х-5)-(х-2)(х-4)(х-5)=0
(х-4)(х-5)(x-3-x+2)=0
(х-4)(х-5)=0 или (x-3-x+2)=0
(х-4)=0 или (х-5)=0
x=4 x=5
2 votes
Thanks 1
Gubaiovaguldana
Х3-20х-3х2-60=х3-20х-2х2-40
х3-20х- 3х2-60-х3+20х+2х2+40
-х2-20=0. (-1)
х2+20=0
х2=-20
1 votes
Thanks 1
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Verified answer
(х-3)(х-4)(х-5)=(х-2)(х-4)(х-5)(х-3)(х-4)(х-5)-(х-2)(х-4)(х-5)=0
(х-4)(х-5)(x-3-x+2)=0
(х-4)(х-5)=0 или (x-3-x+2)=0
(х-4)=0 или (х-5)=0
x=4 x=5
х3-20х- 3х2-60-х3+20х+2х2+40
-х2-20=0. (-1)
х2+20=0
х2=-20