ОДЗ: x ≥ -0,5; x ≥ 8 => x ≥ 8
√(2x + 1) > 3 + √(x - 8)
2x + 1 > 9 + 6√(x-8) + x - 8
x > 6√(x-8)
x² > 36x - 36*8
x² - 36x + 36*8 > 0
D = 36² - 36*32 = 36*4 = 12²
x₁ = (36 + 12)/2 = 24
x₂ = (36-12)/2 = 12
с учетом ОДЗ:
x ∈ [8; 12] U [24; +∞)
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ОДЗ: x ≥ -0,5; x ≥ 8 => x ≥ 8
√(2x + 1) > 3 + √(x - 8)
2x + 1 > 9 + 6√(x-8) + x - 8
x > 6√(x-8)
x² > 36x - 36*8
x² - 36x + 36*8 > 0
D = 36² - 36*32 = 36*4 = 12²
x₁ = (36 + 12)/2 = 24
x₂ = (36-12)/2 = 12
с учетом ОДЗ:
x ∈ [8; 12] U [24; +∞)