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belkapizdelka
@belkapizdelka
August 2022
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Решите пожалуйста номер 3(в); 5(а,б); 6 (а,б)
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andreevnaelina
3в) (b³/f²)^4=b^3*4/f^2*4=b^12/f^8
5a) 49х²у²= 7х*7х*у*у=7²х²у²
5б) -27n³m³= -3nm×3nm×3nm=3³n³m³
6a) 80³*(0,5)³= (80*0,5)³=40³
6б) (-1/6)^4 * 30^4= (1/6)^4 * 30^4=(1/6*30)^4=5^4=625
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Answers & Comments
5a) 49х²у²= 7х*7х*у*у=7²х²у²
5б) -27n³m³= -3nm×3nm×3nm=3³n³m³
6a) 80³*(0,5)³= (80*0,5)³=40³
6б) (-1/6)^4 * 30^4= (1/6)^4 * 30^4=(1/6*30)^4=5^4=625