(4с+13)(с^2+1)-(4c-3)(c+2)^2=4c^3+13c^2+4c+13-4c^3+3c^2-4c+12c-16c+12=16c^2-4c+25
a(a+2)+c(c-2)=a^2+2a+c^2-2c-2ac=(a-c)^2+2(a-c)
a-c=7
7^2+2*7=49+14=63
4x^2-4x+11
x=0
4*0+4*0+11=11-наим.
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(4с+13)(с^2+1)-(4c-3)(c+2)^2=4c^3+13c^2+4c+13-4c^3+3c^2-4c+12c-16c+12=16c^2-4c+25
a(a+2)+c(c-2)=a^2+2a+c^2-2c-2ac=(a-c)^2+2(a-c)
a-c=7
7^2+2*7=49+14=63
4x^2-4x+11
x=0
4*0+4*0+11=11-наим.