100ethereals

Verified answer

1) б-г-д
2) C2H6+Br2(hv)=C2H5Br+HBr
2C2H5Br+2Na=2NaBr+C4H10
CH3-CH2-CH2-CH3=CH3-CH(CH3)-CH3 (изомеризация, кат. AlCl3, t=100ºC)
CH3-CH(CH3)-CH3+6,5O2=4CO2+5H2O
3) CH4+2O2=CO2+H2O
V(O2)=2V(CH4)=10л
V(возд.)=V(O2)/0,21=10л/0,21=46,62 л