Решите пожалуйста, правильно!. Created by Wardog43. algebra-ru

Решите пожалуйста, правильно!...

August 2021 1 8 Report

Решите пожалуйста, правильно!

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diks2004 $\frac{a^3+b^3}{a^3-b^3} * \frac{b-a}{a+b} :(ab-a^2-b^2)= \frac{(a+b)(a^2-ab+b^2)}{(a-b)(a^2-ab+b^2)}* \frac{b-a}{a+b}:(ab-a^2-b^2)=\\
= \frac{b-a}{a-b}:(ab-a^2-b^2)=- \frac{a-b}{a-b}:(ab-a^2-b^2) =- \frac{1}{(ab-a^2-b^2)}$

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