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July 2022
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Решите пожалуйста систему уравнений: х-у=3 2х^2+y^2=9
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OlegPV
Х + 3у = 0, х^2+у^2-2ху=9
х + 3у = 0, (х-у) ^2=9
х + 3у = 0, х-у=3 ------4у= -3----у= -0,75----х=2,25
или х + 3у = 0, х-у= -3 ------4у=3-----у=0,75------х= -2,25
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Answers & Comments
х + 3у = 0, (х-у) ^2=9
х + 3у = 0, х-у=3 ------4у= -3----у= -0,75----х=2,25
или х + 3у = 0, х-у= -3 ------4у=3-----у=0,75------х= -2,25