ΔK=mgh+A
A=ΔK-mgh
A=m(V₁²-V₂²)/2-mgh
A=m(V₁²-V₂²-2gh)/2
A=2(144-36-100)/2=8 Дж
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
ΔK=mgh+A
A=ΔK-mgh
A=m(V₁²-V₂²)/2-mgh
A=m(V₁²-V₂²-2gh)/2
A=2(144-36-100)/2=8 Дж