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dashaaaaariva
@dashaaaaariva
August 2021
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Решите пожалуйста ....
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theburchik
По теореме косинусов:
AC^2=AB^2+BC^2-2AB*BC*cosB
cosB=AB^2+BC^2-AC^2 / 2AB*BC
cosB=289+49-324 / 2*17*7=14 / 238=0,0588 (примерно)
угол B=86,6 (примерно)
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Answers & Comments
AC^2=AB^2+BC^2-2AB*BC*cosB
cosB=AB^2+BC^2-AC^2 / 2AB*BC
cosB=289+49-324 / 2*17*7=14 / 238=0,0588 (примерно)
угол B=86,6 (примерно)