Решите пожалуйста........... Created by КатяСухорукова. algebra-ru

2)=== ==3)64x + = 1664x+ =16 *x 064 +1=16x64 -16x +1 =0x=

Решите пожалуйста...

July 2022 1 6 Report

Решите пожалуйста..........

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bondarevadarya 2) $\frac{2^{5}* 0.5^{-6} }{ 16^{3} }$ =
= $\frac{ 2^{5}* ( \frac{1}{2}) ^{-6} }{ 2^{12} }$ =
= $\frac{ 2^{5}* 2^{6} }{ 2^{12} }$ = $\frac{1}{2}$

3)64x + $x^{-1}$ = 16
64x+ $\frac{1}{x}$ =16 *x $\neq$ 0
64 $x^{2}$ +1=16x
64 $x^{2}$ -16x +1 =0
x= $\frac{1}{8}$

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