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al77op
@al77op
November 2021
2
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Решите, пожалуйста...........
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sedinalana
Verified answer
1
[3∛b/∛b(b-9)+√b/(b-9)]^-2=[3/(b-9)+√b/(b-9)]^-2=[(3+√b)/(√b-3)(√b+3)^-2=
=[1/(√b-3)]^-2=(√b-3)²
2
(√b-3)²-√(b+9)²=b-6√b+9-b-9=-6√b
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OSMANOVA
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Answers & Comments
Verified answer
1[3∛b/∛b(b-9)+√b/(b-9)]^-2=[3/(b-9)+√b/(b-9)]^-2=[(3+√b)/(√b-3)(√b+3)^-2=
=[1/(√b-3)]^-2=(√b-3)²
2
(√b-3)²-√(b+9)²=b-6√b+9-b-9=-6√b