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sobakazabiyaka
@sobakazabiyaka
July 2022
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РЕШИТЕ СИММЕТРИЧЕСКУЮ СИСТЕМУ!!!
(x+y)^2-4(x+y)=45
(x-y)^2-2(x-y)=3
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Dимасuk
Verified answer
Пусть a = x + y; b = x - y.
a² - 4a = 45
a² - 4a - 45 = 0
a² - 4a + 4 - 49 = 0
(a - 2)² - 7² = 0
(a - 2 - 7)(a - 2 + 7) = 0
(a - 9)(a + 5) = 0
a = 9 или a = -5
x + y = 9 или x + y = -5
b² - 2b = 3
b² - 2b - 3 = 0
b² - 2b + 1 - 4 = 0
(b - 1)² - 2² = 0
(b - 1 - 2)(b - 1 + 2) = 0
(b - 3)(b + 1) = 0
b = 3 или b = -1
x - y = 3 или x - y = -1
Решаем четыре системы:
1)
x + y = 9
x - y = 3
2x = 12
x + y = 9
x = 6
y = 3
2)
x + y = 9
x - y = -1
2x = 8
x + y = 9
x = 4
y = 5
3)
x + y = -5
x - y = 3
2x = -2
x + y = -5
x = -1
y = -4
4)
x + y = -5
x - y = -1
2x = -6
x + y = -5
x = -3
y = -2
Ответ: (-3; -2), (-1; -4), (4; 5), (6; 3).
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sobakazabiyaka
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Answers & Comments
Verified answer
Пусть a = x + y; b = x - y.a² - 4a = 45
a² - 4a - 45 = 0
a² - 4a + 4 - 49 = 0
(a - 2)² - 7² = 0
(a - 2 - 7)(a - 2 + 7) = 0
(a - 9)(a + 5) = 0
a = 9 или a = -5
x + y = 9 или x + y = -5
b² - 2b = 3
b² - 2b - 3 = 0
b² - 2b + 1 - 4 = 0
(b - 1)² - 2² = 0
(b - 1 - 2)(b - 1 + 2) = 0
(b - 3)(b + 1) = 0
b = 3 или b = -1
x - y = 3 или x - y = -1
Решаем четыре системы:
1)
x + y = 9
x - y = 3
2x = 12
x + y = 9
x = 6
y = 3
2)
x + y = 9
x - y = -1
2x = 8
x + y = 9
x = 4
y = 5
3)
x + y = -5
x - y = 3
2x = -2
x + y = -5
x = -1
y = -4
4)
x + y = -5
x - y = -1
2x = -6
x + y = -5
x = -3
y = -2
Ответ: (-3; -2), (-1; -4), (4; 5), (6; 3).