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izabella9
@izabella9
August 2022
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решите систему плиз.....
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magicmasha
1) определим одз, х>0 и у>0 по свойству логарифмов;
log2 x -log2 y=1; log2(x/y)=log2 2;
x/y=2; x=2y;
2) x^2-y^2=27; (2y)^2-y^2=27;
(2y-y)(2y+y)=27; y*3y=27; 3y^2=27;
y^2=27/3=9; y=+-3; y1=3; y2=-3 (не подходит по одз);
3) x1=2*3=6;
Ответ: х=6; у=3.
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Answers & Comments
log2 x -log2 y=1; log2(x/y)=log2 2;
x/y=2; x=2y;
2) x^2-y^2=27; (2y)^2-y^2=27;
(2y-y)(2y+y)=27; y*3y=27; 3y^2=27;
y^2=27/3=9; y=+-3; y1=3; y2=-3 (не подходит по одз);
3) x1=2*3=6;
Ответ: х=6; у=3.