Решите систему уравнений: (2Х-1)(у+2)=0х^2-4х+у=-5. Created by myrE. algebra-ru

Решите систему уравнений: (2Х-1)(у+2)=0х^2-4х+у=-5...

August 2022 1 8 Report

Решите систему уравнений:
(2Х-1)(у+2)=0
х^2-4х+у=-5

Answers & Comments

lovenastia111 2x-4x+y=-5
y=-5-2x+4x
y= 2x-5
(2x-1)(2x-5+2)=0
4x2- 10x+4x-2x+5-2=0
4x2-8x+3=0
D=64-48=16
x1=8-4/8=0,5
x2=8+4/8=1,5
y1=2*0,5-5=-4
y2=2*1,5-5=-2
Ответ:0,5;-4 1,5;-2

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