решите систему xy=-10; x^2+y^2=29
xy=-10
x^2+y^2=29
x=-10/y
(100/y^2)+y^2=29
y^2=t
(100/t)+t=29
t^2-29t+100=0
t1=4
t2=25
y1=+-5
y2=+-2
x1=+-2
x2=+-5
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xy=-10
x^2+y^2=29
x=-10/y
(100/y^2)+y^2=29
y^2=t
(100/t)+t=29
t^2-29t+100=0
t1=4
t2=25
y1=+-5
y2=+-2
x1=+-2
x2=+-5