Решите уравнение: 12x^2+3x=0
12x^2 + 3x =0
3x (4x + 1) = 0
3x = 0 ИЛИ 4x + 1 = 0
x = 0 4x = -1
x = -1/4 = - 0,25
Ответ: х1 = 0; х2 = -,025.
12x^2+3x=0
x(12x+3)=0
x=0 12x+3=0
12x=-3
x=-3/12
x=-1/4
ответ х1=0 х2=-1/4
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Verified answer
12x^2 + 3x =0
3x (4x + 1) = 0
3x = 0 ИЛИ 4x + 1 = 0
x = 0 4x = -1
x = -1/4 = - 0,25
Ответ: х1 = 0; х2 = -,025.
Verified answer
12x^2+3x=0
x(12x+3)=0
x=0 12x+3=0
12x=-3
x=-3/12
x=-1/4
ответ х1=0 х2=-1/4