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YanaRomashkova
@YanaRomashkova
August 2022
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Решите уравнение
2^8×7^x+1=98
2 в степени 8 умножить на 7 в степени x+1 равно 98
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sedinalana
Verified answer
128*7^(x+1)=98
7^(x+1)=98/128
7^(x+1)=49/64
x+1=log(7)49/64
x=-1+log(7)49-log(7)64=-1+2+6log(7)2=1+6log(7)2
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Answers & Comments
Verified answer
128*7^(x+1)=987^(x+1)=98/128
7^(x+1)=49/64
x+1=log(7)49/64
x=-1+log(7)49-log(7)64=-1+2+6log(7)2=1+6log(7)2