Решите уравнение:
а) (2х – 5)2 – (2х – 3)(2х + 3) = 0; б) 9у2 – 25 = 0.
a) 4x-10-4x^2+9=0
-4x^2+4x-1=0 |*(-1)
4x^2-4x+1=0
Д= -b^2-4ac=16-16=0
x=-b/2a
x=4/8=1/2=0,5
^2=степень
б)9y^2-25=0
(3y-5)(3y+5)=0
4x^-20x+25-4x^-9=0
4x^-20x-4x^=0-25+9
-20x=-16
x=-16:(-20)
x=0,8
^=2 cтепень
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Answers & Comments
a) 4x-10-4x^2+9=0
-4x^2+4x-1=0 |*(-1)
4x^2-4x+1=0
Д= -b^2-4ac=16-16=0
x=-b/2a
x=4/8=1/2=0,5
^2=степень
б)9y^2-25=0
(3y-5)(3y+5)=0
4x^-20x+25-4x^-9=0
4x^-20x-4x^=0-25+9
-20x=-16
x=-16:(-20)
x=0,8
^=2 cтепень