Решите уравнение:
а) 3(2, 4 - 1, 1x) = 2, 7x + 3, 2
б) 6(x - 1) = 9, 4 - 1, 7y
а) 3(2, 4 - 1, 1x) = 2, 7x + 3, 2
б) 6(x - 1) = 9, 4 - 1, 7y
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Ответ:
а) 3(2,4-1,1х)=2,7х+3,2
7,2-3,3х-2,7х-3,2=0
-6х+4=0
-6х=-4
х=4/6=0,6
Объяснение: