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Алиночка7к
@Алиночка7к
August 2022
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Решите уравнение
а)X³–2x²–x+2=0
б)y³–y²=16y–16
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Answers & Comments
krugly1981
Verified answer
X³ - 2x² - x + 2 = 0
(x³ - 2x²) - (x - 2) = 0
x²( x - 2) - ( x - 2) = 0
( x - 2)(x² - 1) = 0
Произведение равно 0,когда один из множителей равен 0,значит,
x - 2 = 0
x = 2
x² - 1 = 0
x² = 1
x = 1
x = - 1
Ответ: x1 = 2, x2 = 1, x3 = - 1.
y³ - y² = 16y - 16
y²( y - 1) = 16 ( y - 1)
y²( y - 1) - 16( y - 1) = 0
(y - 1)(y² - 16) = 0
(y - 1)(y - 4)(y + 4) = 0
y -1 = 0
y = 1
y - 4 = 0
y = 4
y + 4 =0
y =- 4
Ответ : y1 = 1, y2 = 4, y3 = - 4.
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Answers & Comments
Verified answer
X³ - 2x² - x + 2 = 0(x³ - 2x²) - (x - 2) = 0
x²( x - 2) - ( x - 2) = 0
( x - 2)(x² - 1) = 0
Произведение равно 0,когда один из множителей равен 0,значит,
x - 2 = 0
x = 2
x² - 1 = 0
x² = 1
x = 1
x = - 1
Ответ: x1 = 2, x2 = 1, x3 = - 1.
y³ - y² = 16y - 16
y²( y - 1) = 16 ( y - 1)
y²( y - 1) - 16( y - 1) = 0
(y - 1)(y² - 16) = 0
(y - 1)(y - 4)(y + 4) = 0
y -1 = 0
y = 1
y - 4 = 0
y = 4
y + 4 =0
y =- 4
Ответ : y1 = 1, y2 = 4, y3 = - 4.