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vladpaskevits
@vladpaskevits
June 2022
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Решите уравнение log3 (x^2-4x+3)=log3 (x-1)
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Yatopchic
Log4 (3x+1)=2
log4 (3x+1)= log4 (16)
3x+1=16
3x=15
х=5
2) log3 (x+2)+log3x=1
log3 (x+2)*х= log3(3)
(x+2)*х=3
х^+2x-3=0
D=4+12=16
x=(-2+4):2; x=1
второй отрицательный корень (-3) не входит в область определения.
3)lg (x^2 - 6x+9) = lg3+lg(x+3)
lg (x^2 - 6x+9) = lg3(x+3)
x^2 - 6x+9 = 3(x+3)
x^2 - 9x =0
х=0;
х=9
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Answers & Comments
log4 (3x+1)= log4 (16)
3x+1=16
3x=15
х=5
2) log3 (x+2)+log3x=1
log3 (x+2)*х= log3(3)
(x+2)*х=3
х^+2x-3=0
D=4+12=16
x=(-2+4):2; x=1
второй отрицательный корень (-3) не входит в область определения.
3)lg (x^2 - 6x+9) = lg3+lg(x+3)
lg (x^2 - 6x+9) = lg3(x+3)
x^2 - 6x+9 = 3(x+3)
x^2 - 9x =0
х=0;
х=9