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Докукин9
@Докукин9
July 2022
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Решите уравнение sin2x+sinx=2cosx+1
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sedinalana
Verified answer
2sinxcosx+sinx-(2cosx+1)=0
sinx(2cosx+1)-(cosx+1)=0
(2cosx=1)(sinx-1)=0
cosx=-1/2⇒x=+-2π/3+2πn,n∈z
sinx=1⇒x=π/2+2πk,k∈z
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Verified answer
2sinxcosx+sinx-(2cosx+1)=0sinx(2cosx+1)-(cosx+1)=0
(2cosx=1)(sinx-1)=0
cosx=-1/2⇒x=+-2π/3+2πn,n∈z
sinx=1⇒x=π/2+2πk,k∈z