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oleg5151
@oleg5151
July 2022
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Решите уравнение (x+1)^2=4x
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NochnayaArhideya
Решение:
(х+1)²=4х
х²+2х+1=4х
х²+2х-4х+1=0
х²-2х+1=0
х1,2=1+-√(1-1=1+-√0=1
Ответ: х=1
2 votes
Thanks 4
fiofionina
Verified answer
(х+1)²=4х
х²+2х+1-4х=0
х²-2х+1=0
D= (-2)²-4*1*1= 4-4=0
D=0, 1 корень
х= -(-2)/2*1= 2/2= 1
3 votes
Thanks 7
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Answers & Comments
(х+1)²=4х
х²+2х+1=4х
х²+2х-4х+1=0
х²-2х+1=0
х1,2=1+-√(1-1=1+-√0=1
Ответ: х=1
Verified answer
(х+1)²=4хх²+2х+1-4х=0
х²-2х+1=0
D= (-2)²-4*1*1= 4-4=0
D=0, 1 корень
х= -(-2)/2*1= 2/2= 1