x² = -5i
x₁₂ = +- i√5
------
x² + 3 = √6
x² = √6 - 3
x₁₂ = +- i√(√6 - 3)
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Verified answer
x² = -5i
x₁₂ = +- i√5
------
x² + 3 = √6
x² = √6 - 3
x₁₂ = +- i√(√6 - 3)