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Ekaterina85265
@Ekaterina85265
August 2022
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Решите уравнение (x+3)^4-24(x+3)^2-25=0
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sangers1959
Verified answer
(x+3)⁴-24(x+3)²-25=0
(x+3)²=t≥0
t²-24t-25=0 D=676
t₁=25 t₂=-1∉
(x+3)²=25
x+3=5 x₁=2
x+3=-5 x₂=-8
Ответ: x₁=2 x₂=-8.
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Ekaterina85265
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sangers1959
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Answers & Comments
Verified answer
(x+3)⁴-24(x+3)²-25=0(x+3)²=t≥0
t²-24t-25=0 D=676
t₁=25 t₂=-1∉
(x+3)²=25
x+3=5 x₁=2
x+3=-5 x₂=-8
Ответ: x₁=2 x₂=-8.