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nirlysenko
@nirlysenko
August 2022
1
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Решите уравнение: x^4 + 2x^2 - 3=0
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AnonimusPro
Verified answer
Делаем замену:
y=x^2
получим:
y^2+2y-3=0
D=4+12=16=4^2
y1=(-2+4)/2=1
y2=-6/2=-3
x^2=-3
x- нет корней
x^2=1
x1=1
x2=-1
Ответ: x1=1; x2=-1
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Answers & Comments
Verified answer
Делаем замену:y=x^2
получим:
y^2+2y-3=0
D=4+12=16=4^2
y1=(-2+4)/2=1
y2=-6/2=-3
x^2=-3
x- нет корней
x^2=1
x1=1
x2=-1
Ответ: x1=1; x2=-1