№1
2сos²x-2sinxcosx=0
2cosx(cosx-sinx)=0
cosx=0
x=π/2+πn,n∈z
cosx-sinx=0/cosx
1-tgx=0
tgx=1
ОТВЕТ x=π/4+πk,k∈z
№2
cosx+cos3x=cos2x
2cos2xcosx-cos2x=0
cos2x*(2cosx-1)=0
cos2x=0
2x=π/2+πn
x=π/4+πn/2,n∈z
cosx=1/2
ОТВЕТ x=+-π/3+2πk,k∈z
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Answers & Comments
№1
2сos²x-2sinxcosx=0
2cosx(cosx-sinx)=0
cosx=0
x=π/2+πn,n∈z
cosx-sinx=0/cosx
1-tgx=0
tgx=1
ОТВЕТ x=π/4+πk,k∈z
№2
cosx+cos3x=cos2x
2cos2xcosx-cos2x=0
cos2x*(2cosx-1)=0
cos2x=0
2x=π/2+πn
x=π/4+πn/2,n∈z
cosx=1/2
ОТВЕТ x=+-π/3+2πk,k∈z