2сos²x-2sinxcosx=0
2cosx(cosx-sinx)=0
cosx=0
x=π/2+πn,n∈z
cosx-sinx=0/cosx
1-tgx=0
tgx=1
ОТВЕТ x=π/4+πk,k∈z
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2сos²x-2sinxcosx=0
2cosx(cosx-sinx)=0
cosx=0
x=π/2+πn,n∈z
cosx-sinx=0/cosx
1-tgx=0
tgx=1
ОТВЕТ x=π/4+πk,k∈z