решите уравнения 1.log2(10x)-log2(4x+156)=log2 1-7log7 4
2. log15 (6-35x)*log44(1-2x)=log8 1
3. log2(x+1)+log2(4x+4)=6
2. log15 (6-35x)*log44(1-2x)=log8 1
3. log2(x+1)+log2(4x+4)=6
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решите уравнения1.log2(10x)-log2(4x+156)=log2 1-7log7 4
log2(10x/(4x+156))=0-7[log2 4]/log2 7
все верно в условии???
2. log15 (6-35x)*log44(1-2x)=log8 1
log15 (6-35x)*log44(1-2x)=0 ⇔
1)log15 (6-35x)=0 2) log44(1-2x)=0
(6-35x)=1 x=1/7 1-2x=1 x=0
проверка
log15 (1)*log44(1-2/7)=0 верно log15 (6-0)*log44(1)=0 верно
3. log2(x+1)+log2(4x+4)=6 одз: x+1>0⇔x>-1
(x+1)(4x+4)=2^6
4(x+1)²=4·2^4
(x+1)²=4²
(x+1-4)(x+1+4)=0 x=3 x=-5∉ одз: x>-1