Решите уравнения:
8x(1+2x)-(4x+3)(4x-3)=2
(8-9x)x=-40+(6-3x)(6+3x)
(x-6)²-x(x+8)=2
16x(2-x)+(4x-5)²=1
9x²-1-(3x-2)²=0
(4x-3)(3+4x)-2x(8x-1)=0
8x(1+2x)-(4x+3)(4x-3)=2
(8-9x)x=-40+(6-3x)(6+3x)
(x-6)²-x(x+8)=2
16x(2-x)+(4x-5)²=1
9x²-1-(3x-2)²=0
(4x-3)(3+4x)-2x(8x-1)=0
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Answers & Comments
8х+16х^2-16х^2+9 = 2
8х = -7
х = -7/8
2) 8х-9х^2 = -40+(36-9х^2)
-9х^2+9х^2+8х = -40+36
8х = -4
х= -1/2
3) (х^2-12х+36)-(х^2+8х) = 2
х^2-12х+36-х^2-8х = 2
-20х = 2-36
х = -34/-20
32х-16х^2+16х^2+40+25 = 1
32х = 64
х = 2
5) 9х^2-1-(9х^2+12+4) = 0
9х^2-1-9х^2-12-4 = 0
-1-16 = 0
-17 = 0
6) 16х^2-9-16х^2+2х = 0
2х-9 = 0
х = 4,5