(х+4)^2=3x+40
x^2 + 8x + 16=3x+40
x^2-5x-24=0
D=121
x1=(5+11)\2 = 8
x2=(5-11)\2 = -3
Ответ:8,-3
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(х+4)^2=3x+40
x^2 + 8x + 16=3x+40
x^2-5x-24=0
D=121
x1=(5+11)\2 = 8
x2=(5-11)\2 = -3
Ответ:8,-3