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MsPi
@MsPi
July 2022
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Решитееее!!!!! Срочнооооо!!!!!
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mmb1
Verified answer
По поводу ОДЗ
8^x>0 всегда
3^3x + x^2 - 9 > 0 надо построить графики и посмотреть, но если мы найдет корни, то просто подставим и проверим
3х - log(6) (8^x) = log(6) (3^(3x) + x^2 - 9)
3х - log(6) ((2^3)^x) = log(6) (3^(3x) + x^2 - 9)
3х - log(6) ((2^(3x)) = log(6) (3^(3x) + x^2 - 9)
3х log(6) 6 - 3x * log(6) (2) = log(6) (3^(3x) + x^2 - 9) ( log(6) 6 = 1)
3х ( log(6) 6 - log(6) (2) ) = log(6) (3^(3x) + x^2 - 9)
3х log(6) 3 = log(6) (3^(3x) + x^2 - 9)
log(6) 3^(3x) = log(6) (3^(3x) + x^2 - 9)
3^(3x) = 3^(3x) + x^2 - 9
x^2=9
x=3
x=-3
проверим на ОДЗ
3^(3*3) + 3^2 - 9 > 0 да
3^(-3*3) + (-3)^2 - 9 > 0 да
Ответ -3 и 3
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Answers & Comments
Verified answer
По поводу ОДЗ8^x>0 всегда
3^3x + x^2 - 9 > 0 надо построить графики и посмотреть, но если мы найдет корни, то просто подставим и проверим
3х - log(6) (8^x) = log(6) (3^(3x) + x^2 - 9)
3х - log(6) ((2^3)^x) = log(6) (3^(3x) + x^2 - 9)
3х - log(6) ((2^(3x)) = log(6) (3^(3x) + x^2 - 9)
3х log(6) 6 - 3x * log(6) (2) = log(6) (3^(3x) + x^2 - 9) ( log(6) 6 = 1)
3х ( log(6) 6 - log(6) (2) ) = log(6) (3^(3x) + x^2 - 9)
3х log(6) 3 = log(6) (3^(3x) + x^2 - 9)
log(6) 3^(3x) = log(6) (3^(3x) + x^2 - 9)
3^(3x) = 3^(3x) + x^2 - 9
x^2=9
x=3
x=-3
проверим на ОДЗ
3^(3*3) + 3^2 - 9 > 0 да
3^(-3*3) + (-3)^2 - 9 > 0 да
Ответ -3 и 3