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MsPi
@MsPi
July 2022
1
11
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упростите выражение
x^2-4x/x-3 (x/x-4 + 8/x^2-3x-4 + 2/x+1)
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m11m
х²-4х
* (
х
+
8
+
2
) =
х²-4х
* (
х
+
8
+
2
) =
х-3 ( х-4 х²-3х-4 х+1 ) х-3 ( х-4 (х+1)(х-4) х+1 )
Разложим х²-3х-4 на множители:
х²-3х-4=0
Д=9+4*4=25
х₁=
3-5
=-1
2
х₂=
3+5
=4
2
х²-3х-4=(х+1)(х-4)
=
х²-4х
* (
х(х+1)+8+2(х-4)
) =
х²-4х
*
х²+х+8+2х-8
=
х(х-4)
*
х²+3х
=
х-3 ( (х+1)(х-4) ) х-3 (х+1)(х-4) х-3 (х+1)(х-4)
=
х * (х²+3х)
=
х²(х+3)
(х-3)(х+1) (х-3)(х+1)
11 votes
Thanks 15
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Answers & Comments
х-3 ( х-4 х²-3х-4 х+1 ) х-3 ( х-4 (х+1)(х-4) х+1 )
Разложим х²-3х-4 на множители:
х²-3х-4=0
Д=9+4*4=25
х₁=3-5=-1
2
х₂=3+5=4
2
х²-3х-4=(х+1)(х-4)
=х²-4х * (х(х+1)+8+2(х-4)) = х²-4х * х²+х+8+2х-8 = х(х-4) * х²+3х =
х-3 ( (х+1)(х-4) ) х-3 (х+1)(х-4) х-3 (х+1)(х-4)
=х * (х²+3х) = х²(х+3)
(х-3)(х+1) (х-3)(х+1)