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никусь2222
@никусь2222
July 2022
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Розв'язати нерівність :
(3x-1)(x-4)≥(2x-1)²+21
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Aida050119
3x^2-13x+4=>4x^2-4x+22
-x^2-9x-18=>0
x^2+9x+18<=0
(x+6)(x+3)<=0
ответ: [-6;-3]
1 votes
Thanks 1
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Answers & Comments
-x^2-9x-18=>0
x^2+9x+18<=0
(x+6)(x+3)<=0
ответ: [-6;-3]