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lepaku
@lepaku
July 2022
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розв'яжіть нерівність |х-1|≥ -2
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HSS9860
Verified answer
1.
∡
x-1
≥0, x-1≥2 ⇔ x≥1 & x≥3 ⇒ x≥3
2. ∡x-1<0, 1-x≥2 ⇔ x<1& x≤ -1 ⇒ x≤ -1
x∈(-∞;-1]∩[3;+∞)
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Answers & Comments
Verified answer
1. ∡x-1≥0, x-1≥2 ⇔ x≥1 & x≥3 ⇒ x≥32. ∡x-1<0, 1-x≥2 ⇔ x<1& x≤ -1 ⇒ x≤ -1
x∈(-∞;-1]∩[3;+∞)